Workbooks.OpenText Error "Expected function or variable"
Why does my code below not work? It highlights the .OpenText part and states: Expected function or variable Dim Indata As Excel.Workbook Set Indata = Workbooks.OpenText …
How to programatically define FieldInfo parameter on Workbooks ...
Jul 20, 2018 · The Workbooks.OpenText method takes a parameter called FieldInfo to determine the format types in each column. For example the following code will open a text file and give Columns 1 …
Workbooks.OpenText not parsing csv files properly Excel 2016
Feb 13, 2017 · Workbooks.OpenText not parsing csv files properly Excel 2016 Asked 8 years, 11 months ago Modified 5 years, 4 months ago Viewed 16k times
opentext - REST API to upload PDF's and index values to categories …
Apr 6, 2017 · I want to upload some documents to Open Text via the REST API 's. I have an Open Text CS set up, but I am not able to hit any of the REST API 's. Also, I need to know how to map my …
Opentext content server unable to create/connect to database
Jan 31, 2021 · Opentext content server unable to create/connect to database Asked 4 years, 11 months ago Modified 4 years, 11 months ago Viewed 2k times
.net - Unable to open a file using System.IO.File.OpenText (file path ...
Dec 8, 2016 · Unable to open a file using System.IO.File.OpenText (file path) in C# Asked 9 years ago Modified 9 years ago Viewed 5k times
Gupta Centura/Team Developer guides/manuals/book
Mar 19, 2018 · The toolset is now owned and developed by OpenText ( and is commonly referred to as Gupta ) and the latest release is v7.1 - which is native 64bit , UNICODE and .Net enabled.
metadata - OpenText Content Server Search API: Retrieve a file's ...
Jan 13, 2014 · OpenText Content Server Search API: Retrieve a file's category data via URL link in XMLformat? Asked 12 years, 2 months ago Modified 12 years ago Viewed 7k times
Import semicolon separated CSV file using VBA - Stack Overflow
Oct 6, 2016 · Workbooks.Open fileName:=strPath & "thisFile.csv" data is separated by commas, so it looks like that: The same wrong result pops out when I am using OpenText function
Open csv file delimited by pipe character - Stack Overflow
Exaclty. The only way I could get Workbooks.OpenText to work with a SemiColon delimited .csv was to use the Name method to temporarily change the filename to .txt, load the contents, then finally …